Question

How many moles of electron weighs one kilogram?

• A. $6.023\times {10}^{23}$
• B. $\frac{1}{9.108}\times {10}^{31}$
• C. $\frac{6.023}{9.108}\times {10}^{54}$
• D. $\frac{1}{9.108\times 6.023}\times {10}^5$

Answer 1

The correct option is D

$\frac{1}{9.108\times 6.023}\times {10}^5$

$9.108\times {10}^{-31}kg\to 1e^{-}$

$1kg\to x{e}^{-}$

$x=\frac{1\times 1}{9.108\times {10}^{-31}}$

$noofmoles=\frac{1}{9.108\times {10}^{-31}\times 6.023\times {10}^{23}}$