How many $m o l e s$ of electrons are involved in the conversion of $1 m o l e$ ${C r_{2} O_{7}}^{2 -}$ into $C r^{3 +}$ ion?

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Solution

The balanced ionic reaction for the above conversion is:
${C r_{2} O_{7}}^{2 -} + 14 H^{+} + 6 e^{-} \to 2 C r^{3 +} + 7 H_{2} O$
$∴$ The no. of $m o l e s$ of electrons involved per $m o l e$ of dichromate is $6$ .

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