How many moles of electrons are involved in the reduction of one mole of $M n O_{4}^{-}$ ion in alkaline medium to $M n O_{3}^{-}$ ?

2

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Solution

The correct option is A $2$
Reaction takes place as follows:
$M n O_{4}^{-} + H_{2} O + {2 e}^{-} \to M n O_{3}^{-} + 2 O H^{-}$
So, 2 electrons are involved in reduction of 1 mole of ${M n O}_{4}^{-}$ ion in alkaline medium to ${M n O}_{3}^{-}$ .

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