Question

How many moles of $Mn{O}_4^{⊝}$ ion will react with $1$ mol of ferrous oxalate in acidic medium?

• A. $\frac{1}{5}$
• B. $\frac{2}{5}$
• C. $\frac{3}{5}$
• D. $\frac{5}{3}$

Answer 1

Answer: (C)

$\frac{3}{5}$

$Fe{C}_2{O}_4\rightleftharpoons F{e}^{2+}+C_2{O}_4^{2-}$

$Mn{O}_4^{⊝}$ oxidises $F{e}^{2+}$ and $C_2{O}_4^{2-}$ both.

$F{e}^{2+}+C_2{O}_4^{2-}\to F{e}^{3+}+2C{O}_2+3e^{-}$

$Mn{O}_4^{⊝}+5e^{-}\to M{n}^{2+}$

$5Fe{C}_2{O}_4\equiv 3Mn{O}_4^{⊝}$

$1Fe{C}_2{O}_4\equiv \frac{3}{5}Mn{O}_4^{⊝}$