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Question

The number of moles of oxalate ions oxidized by one mole of MnO4 ion in acidic medium. 
  1. 52
  2. 25
  3. 35
  4. 53


Solution

The correct option is A 52
Using,
Equivalents of C2O24= equivalents of MnO4

Moles×n factor of C2O24=Moles×n factor of MnO4

putting values,

Moles×2=1×5
Moles=52

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