How many moles of electrons are involved in the reduction of one mole of ${M n O}_{4}^{-}$ ion in an alkaline medium to ${M n O}_{3}^{-}$ ?

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Solution

The correct option is A 2
In alkaline medium, the reduction reaction is as given below:
${M n O}_{4}^{-} \to {M n O}_{3}^{-}$
$+ 7$ $+ 5$
So, two moles of electrons are accepted by the reactant.

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How many mole of electrons are involved in the reduction of one mole of $M n O_{4}^{-}$ ion in alkaline medium to $M n O_{4}^{- 2}$ ?

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