How many moles of helium gas occupy 22-4L at 0- C at 1 atm pressure-

The correct option is C 1.0 mole pV=nRT n= pV RT #160; #160; = 1atm( 22.4L ) #160; ( 0.082Latm/molK ) 273K n=1 mole 1 mo ...

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Standard IX

Chemistry

Mole Concept & Avogadro Number

How many mole...

Question

How many moles of helium gas occupy $22.4 L$ at $0^{\circ} C$ at $1$ atm pressure?

0.11

mole

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0.90

mole

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1.0

mole

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1.11

mole

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Solution

The correct option is C $1.0$ mole
$p V = n R T$

$n = \frac{p V}{R T}$

$= \frac{1 a t m (22.4 L)}{(0.082 L a t m / m o l K) 273 K}$

$n = 1$ mole

$1$ mole of the gas occupies $22.4 L$ at $O^{\circ} C$ at $1 a t m$ pressure.

Hence, the correct option is C.

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How many moles of helium gas occupy 22.4L at 0∘C at 1 atm pressure?

The correct option is C 1.0 molepV=nRTn=pVRT =1atm(22.4L)(0.082Latm/molK)273Kn=1 mole1 mole of the gas occupies 22.4L at O∘C at 1atm pressure.Hence, the correct option is C.

How many moles of helium gas occupy $22.4 L$ at $0^{\circ} C$ at $1$ atm pressure?

The correct option is C $1.0$ mole
$p V = n R T$

$n = \frac{p V}{R T}$

$= \frac{1 a t m (22.4 L)}{(0.082 L a t m / m o l K) 273 K}$

$n = 1$ mole

$1$ mole of the gas occupies $22.4 L$ at $O^{\circ} C$ at $1 a t m$ pressure.

Hence, the correct option is C.