How many moles of iodine are liberated when $1$ mole of potassium dechromate reacts with potassium iodide in acidic medium ?

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $3$
The balanced chemical equation to represent the reaction is

$K_{2} C r_{2} O_{7} + 6 K I + 12 H_{2} S O_{4} \to K_{2} S O_{4} + C r_{2} (S O_{4})_{3} + H_{2} O + 3 I_{2} + 6 K O H$

Hence, 3 moles of iodine will be liberated

Suggest Corrections

Similar questions

How many moles of iodine are liberated when 1 mole of potassium dichromate reacts with potassium iodide?

K_{2} C r_{2} O_{7}

2

K M n O_{4}

K I

Join BYJU'S Learning Program