How many moles of iron can be made from the excess of $F e_{2} O_{3}$ using 16 mol of carbon monoxide in the following reaction?
$F e_{2} O_{3} + 3 C O \to 2 F e + 3 C O_{2}$

11.22

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15.38

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10.67

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8.25

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Solution

The correct option is C 10.67
The balanced equation is:
$F e_{2} O_{3} + 3 C O \to 2 F e + 3 C O_{2}$

3 mol of $C O$ are used to produce 2 mol $F e$ .
16 mol of $C O$ will be used to produce = $\frac{2}{3} \times 16$ = 10.67 mol of $F e$

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F e_{2} O_{3}

F e_{2} O_{3} + 3 C O \to 2 F e + 3 C O_{2}

F e_{2} O_{3}

F e_{2} O_{3} + 3 C O \to 2 F e + 3 C O_{2}

How many moles of iron can be made from $F e_{2} O_{3}$ by the use of 16 mol of CO in the following reaction?

$F e_{2} O_{3}$ + 3CO $\to$ 2Fe +3 $C O_{2}$

{F e}_{2} O_{3} + 3 C O ⟶ 2 F e + 3 C O_{2}

F e_{2} O_{3} + 3 C O \to 2 F e + 3 C O_{2}

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