Question

How many moles of iron can be made from the excess of $F{e}_2{O}_3$ using 16 mol of carbon monoxide in the following reaction?
$F{e}_2{O}_3+3CO\to 2Fe+3C{O}_2$

• A. 11.22
• B. 15.38
• C. 10.67
• D. 8.25

Answer 1

The correct option is C 10.67

The balanced equation is:
$F{e}_2{O}_3+3CO\to 2Fe+3C{O}_2$

3 mol of $CO$ are used to produce 2 mol $Fe$.
16 mol of $CO$ will be used to produce = $\frac{2}{3}\times 16$ = 10.67 mol of $Fe$