Question

# How many moles of lead (II) chloride will be formed from a reaction between 6.5 g of PbO and 3.2 g of HCl? [Atomic wt. of Pb=207 g/mol]

A
0.011
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B
0.029
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C
0.044
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D
0.333
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Solution

## The correct option is C 0.029The balanced reaction is as follows : PbO+2HCl→PbCl2+H2OMass given: 6.5 g 3.2 gNo. of moles: 6.5223 3.236.5 =0.029 =0.087Ratio of moles given and stoichiometry 0.0291 0.0872coefficient: =0.029 =0.0435As 0.029 is lower than 0.0435, PbO is limiting reagent and product will form according to the number of moles of PbO (given).So, moles produced of PbCl2=11×0.029=0.029 moles.Hence the correct option is B.

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