Question

How many moles of MgIn2S4 can be made from 1g each of mg, In, and S? (Atomic mass: Mg =24, In = 114.8, S = 32)

Answer 1

The balanced reaction for the above question is as follow

Mg + 2 In + 4 S → MgIn2S4

Here number of moles of each element is :-

n of Mg = 1/ 24 = 0.04

n of In = 0.008

n of S = 0.031

Since the number of moles for In is least therefore it is the limiting reagent.

2 moles of In gives 1 mole of MgIn2S4

Therefore

1 mole of In → 0.5 mole of MgIn2S4

0.008 mole of In → 0.5 × 0.008 moles of MgIn2S4

0.008 mole of In → 0.004 moles of MgIn2S4

Mass of = molar mass × number of moles

Therefore MgIn2S4 = 0.004 × 381.6

Hence number of moles produced is equal to 0.004 moles and amount of product formed = 1.52 g