Question

How many moles of NaCl are present in 200 mL of 0.5 M NaCl solution?

• A.
  1 mol
• B.
  0.1 mol
• C.
  0.5 mol
• D.
  2 mol

Answer 1

The correct option is B

0.1 mol
$\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of Solution(in litres)}}0.5=\frac{\text{Moles of solute}}{200}\times 1000$
$Molesofsolute=\frac{0.5\times 200}{1000}=0.1mol$