How many moles of $S O_{2}$ can be made by using $0.5 m o l$ of $S_{8}$ in the following reaction?
$S_{8}$ + $8 O_{2}$ $\to$ $8 S O_{2}$

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Solution

The correct option is B 4
$S_{8} + 8 O_{2}$ $\to$ $8 S O_{2}$
From the balanced chemical equation, $1 m o l$ of $S_{8}$ reacts to form $8 m o l$ of $S O_{2}$ .
So, from $0.5 m o l$ of $S_{8}$ , the number of moles of $S O_{2}$ formed is,
$0.5 \times 8 = 4$ .

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