The correct option is D 62
Multiples of 3 between 20 and 205 are:
21,24,27,........,204
This sequence forms an AP. with first term a=21 , common difference d=24−21=3 and last term l=204
Since, l=a+(n−1)d
⇒204=21+(n−1)3
⇒204−21=(n−1)3
⇒183=(n−1)3
⇒61=n−1
⇒n=62
Option C is correct.