How many natural number lie between square of the following numbers?
$90$ and $91$

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Solution

We know that
No. of natural numbers between the squares of $90$ and $91 = (91^{2} - 90^{2}) - 1$
By further calculations
$= (91 + 90 - 1)$
So we get
$= 181 - 1$
$= 180$

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