How many non axial d-orbitals are involved in hybridization of X?

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Solution

The correct option is D 0
When a mixture containing chloride ion is heated with $K_{2} C r_{2} O_{7}$ and concentrated $H_{2} S O_{4}$ , deep orange-red fumes of chromyl chloride $(C r O_{2} C l_{2})$ are formed.
$K_{2} C r_{2} O_{7} + 4 N a C l + 6 H_{2} S O_{4} \to 2 K H S O_{4} + 4 N a H S O_{4} + 2 C r O_{2} C l_{2} ↓ + 3 H_{2} O$
$Orange-red fumes$

So in this case, X is $C r O_{2} C l_{2}$ .

Oxidation state of $C l = - 1, O = - 2, C r = x$
$x + 2 \times (- 2) + 2 \times (- 1) = 0 \Rightarrow x = + 6$

Oxidation State of $C r = + 6$

Electronic configuration of $C r^{+ 6} = [A r] 3 d^{0} 4 s^{0}$

Since orbitals doesn't have any electrons in d-orbitals, therefore zero non-axial d-orbitals are involved in hybridization of $C r O_{2} C l_{2}$

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