The digits are 1, 2, 3, 4, 5. We have to form number greater than 24000. Required number will be = (Total) - (Those beginning with 1) - (Those beginning with 21) - (Those beginning with 23) =5!−4!−3!−3!=120−24−6−6=84
How many 4 digit numbers greater than 5000 can be formed by using the digits 2, 3, 5, 6, 7 and 8 such that digits can get repeated?