How many numbers greater than $24, 000$ can be formed by using digits $1$ , $2$ , $3$ , $4$ , $5$ when no digit is repeated

36

No worries! We‘ve got your back. Try BYJU‘S free classes today!

60

No worries! We‘ve got your back. Try BYJU‘S free classes today!

84

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

120

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $84$
The digits are 1, 2, 3, 4, 5. We have to form number greater than 24000. Required number will be = (Total) - (Those beginning with 1) - (Those beginning with 21) - (Those beginning with 23)

$⟹ 5! - 4! - 3! - 3! = 120 - 24 - 6 - 6$

Hence the numbers greater than 24,000 that can be formed here = 84

Suggest Corrections

Similar questions

4 - d i g i t

2300

0, 1, 2, 3, 4, 5

6

56000

4, 5, 6, 7, 8

1000

1, 2, 3, 4, 5, 6

How many 4 digit numbers greater than 5000 can be formed by using the digits 2, 3, 5, 6, 7 and 8 such that digits can get repeated?

Join BYJU'S Learning Program