How many odd numbers less than 1000 can be formed by using the digits 0, 3, 5, 7 when repetition of digits is not allowed ?
How many odd numbers less than 1000 can be formed by using the digits 0, 3, 5, 7 when repetition of digits is not allowed ?
Any number less than 1000 may be any of a number from one-digit number, two-digit number and three-digit number. One-digit odd number :
3 possible ways are there. Th.ese numbers are 3 or 5 or 7. Two-digit odd number :
Tens place can be filled up by 3 ways (using any of the digit among 3, 5 and 7) and then the ones place can be filled in any of the remaining 2 digits.
So, there are 3 × 2= 6 such 2-digit numbers. Three-digit odd. number :
Ignore the presence of zero at ones place for some instance. Hundreds place can be filled up in 3 ways (using any of the digit among 3, 5 and 7), then tens place in 3 ways by using remaining 3 digits (after using a digit, there will be three digits) and then the ones place in 2 ways. So, there are a total of 3×3×2=18 numbers of 3-digit numbers which includes both odd and even numbers (ones place digit are zero). In order to get the odd numbers, it is required to ignore the even numbers i.e. numbers ending with zero.
To obtain the even 3-digit numbers, ones place can be filled up in 1 way (only 0 to be filled), hundreds place in 3 ways (using any of the digit among 3, 5, 7) and then tens place in 2 ways (using remaining 2 digits after filling up hundreds place).
So, there are a total of 1×3×2=6 even 3-digit numbers using the digits 0, 3, 5 and 7 (repetition not allowed) So, number of three-digit odd numbers using the digits 0, 3, 5 and 7 (repetition not allowed) = 18 - 6 = 12
Therefore, odd numbers less than 1000 can be formed by using the digits 0, 3, 5, 7 when repetition of digits is not allowed are 3 + 6 + 12 = 21.
Any number less than 1000 may be any of a number from one-digit number, two-digit number and three-digit number. One-digit odd number :
3 possible ways are there. Th.ese numbers are 3 or 5 or 7. Two-digit odd number :
Tens place can be filled up by 3 ways (using any of the digit among 3, 5 and 7) and then the ones place can be filled in any of the remaining 2 digits.
So, there are 3 × 2= 6 such 2-digit numbers. Three-digit odd. number :
Ignore the presence of zero at ones place for some instance. Hundreds place can be filled up in 3 ways (using any of the digit among 3, 5 and 7), then tens place in 3 ways by using remaining 3 digits (after using a digit, there will be three digits) and then the ones place in 2 ways. So, there are a total of 3×3×2=18 numbers of 3-digit numbers which includes both odd and even numbers (ones place digit are zero). In order to get the odd numbers, it is required to ignore the even numbers i.e. numbers ending with zero.
To obtain the even 3-digit numbers, ones place can be filled up in 1 way (only 0 to be filled), hundreds place in 3 ways (using any of the digit among 3, 5, 7) and then tens place in 2 ways (using remaining 2 digits after filling up hundreds place).
So, there are a total of 1×3×2=6 even 3-digit numbers using the digits 0, 3, 5 and 7 (repetition not allowed) So, number of three-digit odd numbers using the digits 0, 3, 5 and 7 (repetition not allowed) = 18 - 6 = 12
Therefore, odd numbers less than 1000 can be formed by using the digits 0, 3, 5, 7 when repetition of digits is not allowed are 3 + 6 + 12 = 21.
