How many odd numbers less than $1000$ can be formed by using the digits $0, 3, 5, 7$ when repetition of digits is not allowed?

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Solution

No. of odd numbers less than $1000$ can be formed $=$ No of digits can be placed at hundred's place $\times$ ten's place $\times$ units place
$= 3 \times 4 \times 3$
$= 36$

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How many odd numbers less than 1000 can be formed by using the digits 0, 2, 5, 7 when the repetition of digits is allowed ?

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