How many persons can be accommodated in a big-hall of dimensions $40 m, 25 m$ and $15 m$ , assuming that each person requires $5 m^{3}$ of air.

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Solution

$\begin{matrix} T o t a l n o . o f p e r s o n s = \frac{d i m e n s i o n s o f b i g - h a l l}{s p a c e e a c h p e r s o n r e q u i r e s} = \frac{40 \times 25 \times 15}{5} = 40 \times 25 \times 3 = 3000 H e n c e, n u m b e r o f p e r s o n s c a n b e a c c o m m i d a t e d i n a b i g - h a l l = 3000. \end{matrix}$

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State true or false:

The number of persons that can be accommodated in a big hall of dimensions

40 m, 25 m, 15 m

, assuming that each person requires

5 m^{3}

of air are

3000

How many persons can be accommodated in a dining hall of dimensions $(20 m \times 15 m \times 4.5 m)$ , assuming that each person requires $5 m^{3}$ of air?

(a) 250 (b) 270 (c) 320 (d)300

Q. How many persons can be accommodated in a dining hall of dimensions (20 m × 15 m × 4.5 m), assuming that each person requires 5 m³ of air?
(a) 250
(b) 270
(c) 320
(d) 300

Q. How many persons can be accommodated in a dining hall of dimensions

(20 m \times 16 m \times 4.5 m)

, assuming that each person requires

5

cubic meters of air.

Q. How many persons can be accommodated in a dining hall of dimensions (20 m × 16 m × 4.5 m), assuming that each person requires 5 cubic metres of air?

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How many persons can be accommodated in a big-hall of dimensions 40 m, 25 m and 15 m, assuming that each person requires 5 m3 of air.

Totalno.ofpersons=dimensionsofbig−hallspaceeachpersonrequires=40×25×155=40×25×3=3000Hence,numberofpersonscanbeaccommidatedinabig−hall=3000.

How many persons can be accommodated in a big-hall of dimensions $40 m, 25 m$ and $15 m$ , assuming that each person requires $5 m^{3}$ of air.