How many persons can be accommodated in a dining hall of dimensions (20 m × 15 m × 4.5 m), assuming that each person requires 5 m³ of air?
(a) 250
(b) 270
(c) 320
(d) 300

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Solution

(b) 270

Number of persons = $\frac{volume of the hall}{volume of air required by 1 person}$

$= \frac{20 \times 15 \times 4.5}{5} = 20 \times 3 \times 4.5 = 270$

∴ 270 persons can be accommodated.

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How many persons can be accommodated in a dining hall of dimensions $(20 m \times 15 m \times 4.5 m)$ , assuming that each person requires $5 m^{3}$ of air?

(a) 250 (b) 270 (c) 320 (d)300

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How many persons can be accommodated in a dining hall of dimensions (20 m × 15 m × 4.5 m), assuming that each person requires 5 m3 of air? (a) 250 (b) 270 (c) 320 (d) 300

(b) 270 Number of persons = volume of the hallvolume of air required by 1 person =20×15×4.55=20×3×4.5=270 ∴ 270 persons can be accommodated.

How many persons can be accommodated in a dining hall of dimensions (20 m × 15 m × 4.5 m), assuming that each person requires 5 m³ of air?
(a) 250
(b) 270
(c) 320
(d) 300

(b) 270

Number of persons = $\frac{volume of the hall}{volume of air required by 1 person}$

$= \frac{20 \times 15 \times 4.5}{5} = 20 \times 3 \times 4.5 = 270$

∴ 270 persons can be accommodated.