How many persons can be accommodated in a dining hall of dimensions (20 m × 16 m × 4.5 m), assuming that each person requires 5 cubic metres of air?

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Solution

Volume of the dining hall = $(20 \times 16 \times 4.5) m^{3} = 1440 m^{3}$

Volume of air required by each person = 5 m³

∴ Capacity of the dining hall = $\frac{volume of dining hall}{volume of air required by each person} = \frac{1440}{5} = 288 persons$

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(a) 250 (b) 270 (c) 320 (d)300

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(c) 320
(d) 300

How many persons can be accommodated in a hall of length $16 m$ . breadth $12.5 m$ and height $4.5 m$ , assuming that $3.6 m^{3}$ of air is required for each person?

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How many persons can be accommodated in a dining hall of dimensions (20 m × 16 m × 4.5 m), assuming that each person requires 5 cubic metres of air?

Volume of the dining hall = (20×16×4.5) m3=1440 m3 Volume of air required by each person = 5 m3 ∴ Capacity of the dining hall = volume of dining hallvolume of air required by each person=14405=288 persons

Volume of the dining hall = $(20 \times 16 \times 4.5) m^{3} = 1440 m^{3}$

Volume of air required by each person = 5 m³

∴ Capacity of the dining hall = $\frac{volume of dining hall}{volume of air required by each person} = \frac{1440}{5} = 288 persons$