How many PGAL are produced by glycolysis of 3 molecules of glucose? How many ATP are released by respiration of these PGAL till formation of $O_{2}$ and $H_{2} O$ ?

4 PGAL-80 ATP

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6 PGAL-160 ATP

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4 PGAL40 ATP

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6 PGAL-120 ATP

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Solution

The correct option is C 6 PGAL-120 ATP
Glycolysis of one molecule of glucose produces 2 PGAL, thus of three molecules will produce 6 PGAL.
Respiration of one molecule of glucose or 2 PGAL produces 38 ATP molecules, thus, of 6 PGAL will produce 114 ATP molecules. Out of the given options 120 ATP is the nearest correct answer. Thus the correct answer is option D.

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