Question

How many PGAL are produced by glycolysis of 3 molecules of glucose? How many ATP are released by respiration of these PGAL till formation $C{O}_2$ and $H_{2}O$?

• A. 4 PGAL-40 ATP
• B. 6 PGAL-114 ATP
• C. 4 PGAL-80 ATP
• D. 6 PGAL-160 ATP

Answer 1

The correct option is B 6 PGAL-114 ATP

Respiration of 1 molecule of glucose or 2 PGAL produces 38 ATP molecules, therefore 3 molecule of glucose, will produce 6 PGAL and 38×3=114 ATP molecules. So, the correct answer is "option b".