Question

How many spherical bullets can be made out of a solid cube of lead whose edge measures 44 cm, each bullet being 4 cm in diameter?

Answer 1

Edges of a solid cube$=44cm\therefore Volume=a^3=(44{)}^{3}c{m}^3=44\times 44\times 44c{m}^3$
Diameter of a spherical bullet = 4 cm
$\therefore$ Radius $\left(r\right)=\frac{4}{2}=2cm$
Now volume of one bullet $=\frac{4}{3}\pi r^3=\frac{4}{3}\times \frac{22}{7}\times 2\times 2\times 2c{m}^3=\frac{704}{21}c{m}^3$
Now number of bullets from the cube
$=\frac{Volumeofcube}{Volumeofonebullet}$

$=\frac{44\times 44\times 44\times 21}{704}$

$=\frac{1788864}{704}$

$=2541$