Question

How many square tiles of side 18 cm will be required to pave the floor of a rectangular room 5.4 m $\times$ 4.8 m?

Answer 1

Length of the floor =5.4 m =540 cm
Breadth of the floor =4.8 m =480 cm
Area of the floor =540$\times$ 480 sq. cm =259200 sq. cm
Area of one tile =18 $\times$ 18 sq. cm =324 sq. cm
Number of tiles required $=\frac{259200}{324}=800$