Question

A rectangular hall is 12 m long and 6 m broad. Its flooring is to be made of square tiles of side 30 cm. How many tiles will fit in the entire hall ? How many would be required if tiles of side 15 cm were used?

Answer 1

Length of the rectangular hall, l = 12 m
Breadth of the rectangular hall, b = 6 m
Area of the floor of the rectangular hall = l × b
= 12 × 6
= 72 m²
Length of each side of square tile used in the first case = 30 cm
= $\frac{30}{100}m=0.3m$ (∵ 100 cm = 1 m)
Area of each tile = side × side
= 0.3 × 0.3
= 0.09 m²
∴ Required number of square tiles each of side 30 cm =$\frac{\text{area of floor}}{\text{area of each tile}}$
=$\frac{72}{0.09}$
=$\frac{72\times 100}{9}$
= $800$ tiles.
Length of each side of square tile used in the second case = $15cm=\frac{15}{100}m=0.15m$
Area of each tile = side × side
= 0.15 × 0.15
= 0.0225 m²
∴ Required number of square tiles each of side 15 cm = $\frac{\text{area of floor}}{\text{area of each tile}}$
=$\frac{72}{0.0225}$
=$\frac{72\times 10000}{225}$
=$3200$ tiles