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Question

How many terms of the G.P. 3, 32,34,.... be taken together to make 3069512 ?

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Solution

3,32,34,....is a G.P.

and Sn=3069512,a=3,r=12

Sn=a(1rn)1r

3069512=3(1(12)n)112

3069512=3×2×(2n1)2n

1023.2n=1024.2n1024

1024=2n

210=2n

n=10


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