How many three-digit numbers are possible using the digits 2, 4, and 6 without repetition?

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Solution

The correct option is B 6
We know that, systematic listing helps in listing of all possible outcomes for an event in an organised/systematic way.
The possible numbers are:
(i) 246
(ii) 264
(iii) 426
(iv) 462
(v) 642
(vi) 624

$∴$ there are six numbers that can be formed using the given digits.

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