Question

How many times has a solution of pH 2 higher acidity than solution of pH 6?

• A. $10,000$
• B. $12$
• C. $400$
• D. $4$

Answer 1

The correct option is A $10,000$

When $pH=2$,

$pH=-log\left[H^{+}\right]=2$

$\Rightarrow [H^{+}{]}_1={10}^{-pH}={10}^{-2}$

When $pH=6$,

$pH=-log\left[H^{+}\right]=6$

$\Rightarrow [H^{+}{]}_2={10}^{-pH}={10}^{-6}$

Acidity in $pH=2$ is higher than in $pH=6$ by $\frac{\left[H_1^{+}\right]}{\left[H_2^{+}\right]}=\frac{{10}^{-2}}{{10}^{-6}}={10}^4=10,000$