How many water molecules are present in the balanced chemical equation of the following reaction?
$C H_{4} + O_{2} \to C O_{2} + H_{2} O$

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Solution

The correct option is B 2
A balanced chemical equation has an equal number of atoms on both sides of a chemical reaction.
For the given equation:
$C H_{4} + O_{2} \to C O_{2} + H_{2} O$
The number of carbon (C) atoms on the reactant side = number of carbon atoms on the product side.
Number of oxygen (O) atoms on the reactant side = 2
Number of oxygen (O) atoms on the product side = 3
So, we will multiply 2 on the left-hand side to $O_{2}$ and the right-hand side to $H_{2} O$ . Now, the number of hydrogen atoms and oxygen atoms are the same on both sides of the equation and the balanced equation is:
$C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O$
So, there are 2 water molecules present in the balanced chemical equation.

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