How many words can be formed with the letters of the word $^{'} O M E G A^{'}$ such that $O$ and $A$ occupy end places

12

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24

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18

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48

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Solution

The correct option is A $12$
O_ _ _ _ _A
The three letters can be arranged in $3! = 6$ while $o$ and $a$ can exchange their places.
Number of ways = $3! \times 2! = 12$

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