How many words can be formed with the letters of the word $^{'} O M E G A^{'}$ when $E$ being always in the middle

12

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18

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24

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48

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Solution

The correct option is C $24$
OMEGA
$\Rightarrow$ Remaning letters $= 4$
Number of blanks $= 4$
Number of words $= 4!$
$= 4 \times 3 \times 2 \times 1$
$= 24$ Words

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