Question

How many zeros are present at the end of a number which is the product of the first 100 multiples of 10?

Answer 1

First $100$ multiple of $10$ are $=10x20x30x.....x1000$
= ${10}^{100}$ (1 x 2 x 3 x .....x 100)
= ${10}^{100}\times {10}^{24}\times N$
= ${10}^{124}\times N$
Where $N$ is not divisible by $10$
So there are $124$ zero at the end of first $100$ multiple of $10$