How much acceleration will be produced in a body of mass $10 k g$ acted upon by a force of $2 k g f$ ? $(g = 9.8 m s^{- 2})$

19.6 m s^{- 2}

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196 m s^{- 2}

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1.96 m s^{- 2}

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0.196 m s^{- 2}

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Solution

The correct option is B $1.96 m s^{- 2}$
We know that $1 N = 0.102 k g f$ . Given a force of 2 kgf which is also equal to $20 N$ approximately.
$F = m \times a$ .
$F = 10 \times a$
$20 = 10 \times a$
$a = 2 m / s^{2}$ .
Hence acceleration is almost 1.96 $m / s^{2}$ .

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How much acceleration will be produced in a body of mass 10kg acted upon by a force of 2kgf ? (g=9.8ms−2)

The correct option is B 1.96ms−2We know that 1N=0.102kgf. Given a force of 2 kgf which is also equal to 20N approximately.F=m×a.F=10×a20=10×aa=2m/s2.Hence acceleration is almost 1.96 m/s2.

How much acceleration will be produced in a body of mass $10 k g$ acted upon by a force of $2 k g f$ ? $(g = 9.8 m s^{- 2})$

The correct option is B $1.96 m s^{- 2}$
We know that $1 N = 0.102 k g f$ . Given a force of 2 kgf which is also equal to $20 N$ approximately.
$F = m \times a$ .
$F = 10 \times a$
$20 = 10 \times a$
$a = 2 m / s^{2}$ .
Hence acceleration is almost 1.96 $m / s^{2}$ .