Question

How much amount of $CaC{O}_3$ in gram having percentage purity 50 per cent produces 0.56 litre of $C{O}_2$ at on heating?

Answer 1

$CaC{O}_3\to CaO+C{O}_2$

$0.56lt$ of $C{O}_2=\frac{0.56}{22.4}=\frac{1}{40}$ mol.

$\therefore \frac{1}{40}$ mol of $CaC{O}_3$ required = $2.5gm$

$\therefore$ sample is only $50\%$ pure , thus $5gm$ of $CaC{O}_3$ is required.