Question

How much amount of $N{H}_3$ is produced when 28 g of nitrogen react with 6 g of hydrogen?

• A. 28 g
• B. 6 g
• C. 34 g
• D. 32.5 g

Answer 1

The correct option is C 34 g

According to the law of conservation of mass, the total mass of the products is equal to that of reactants, in a chemical reaction.

$3H_2\left(g\right)+N_2\left(g\right)\to 2{\mathrm{NH}}_3\left(g\right)6g28gXg$

The mass of $N{H}_3$ produced is equal to the sum of mass of hydrogen and nitrogen that reacted to give $N{H}_3$.

Hence, the mass of $N{H}_3$ = X g = 28+6 = 34 g.