How much amount of work needs to be done to increase the velocity of an object from $4 m s^{- 1}$ to $6 m s^{- 1}$ , if the mass of the object is $10 k g$ .

100 J

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200 J

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250 J

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500 J

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Solution

The correct option is A $100 J$
Given,
Mass, $m = 10 k g$
Initial velocity, $u = 4 m s^{- 1}$
Final velocity, $v = 6 m s^{- 1}$
We know that,
Work done = change in kinetic energy
Change in K.E $= \frac{1}{2} m (v^{2} - u^{2})$
$= \frac{1}{2} \times 10 \times (6^{2} - 4^{2})$
$= \frac{1}{2} \times 10 \times (20)$
$= \frac{200}{2}$
$= 100 J$

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