CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

How much $$CO_2$$ can be produced when $$36$$ grams of carbon reacts with $$64$$ grams of oxygen gas according to the following reaction?
 $$C(s) + O_{2}(g) \rightarrow CO_{2}(g)$$


A
36 grams
loader
B
64 grams
loader
C
28 grams
loader
D
132 grams
loader
E
88 grams
loader

Solution

The correct option is D $$88\ grams$$
Moles of $$C$$$$=$$ 36/12$$=$$$$3 \ moles$$
Moles of $$O_2$$$$=$$ 64/32$$=$$$$2 \ moles$$
so $$O_2$$ is limiting reagent.
Above reaction is balanced so 
                                              no. of $$CO_2$$ produced $$=$$ no. of $$O_2$$ consumed
so no. of $$CO_2$$ produced $$=$$$$2 \ moles$$
     $$=$$2*44$$=$$$$88 \ grams$$

Chemistry

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image