Question

# How much $$CO_2$$ can be produced when $$36$$ grams of carbon reacts with $$64$$ grams of oxygen gas according to the following reaction? $$C(s) + O_{2}(g) \rightarrow CO_{2}(g)$$

A
36 grams
B
64 grams
C
28 grams
D
132 grams
E
88 grams

Solution

## The correct option is D $$88\ grams$$Moles of $$C$$$$=$$ 36/12$$=$$$$3 \ moles$$Moles of $$O_2$$$$=$$ 64/32$$=$$$$2 \ moles$$so $$O_2$$ is limiting reagent.Above reaction is balanced so                                               no. of $$CO_2$$ produced $$=$$ no. of $$O_2$$ consumedso no. of $$CO_2$$ produced $$=$$$$2 \ moles$$     $$=$$2*44$$=$$$$88 \ grams$$Chemistry

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