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Question

# Methane undergoes a combustion reaction according to the reaction CH4(g)+2O2(g)→CO2(g)+2H2O(l). How many grams of methane gas were burned if 67.2 L of carbon dioxide gas are produced in the reaction? (assume STP)

A
16 grams
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B
48 grams
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C
3 grams
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D
132 grams
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E
22.4 grams
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Solution

## The correct option is B 48 gramsAt STP, 1 mole of any gas occupies a volume of 22.4 L.The volume of 67.2 L corresponds to 67.222.4=3 moles.1 mole of CO2 is obtained from 1 mole of CH4.3 moles of CH4 will be obtained from 3 moles of CO2.The molar mass of methane is 16 g/mol.The mass of 3 moles of methane will be 3×16=48g

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