How much copper in grams can be obtained from $100 g$ of copper sulphate $({C u S O}_{4})$ ?

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Solution

Atomic mass of $C u = 63.5 g$
Now
Molar mass of $C u S O_{4} = 159.5 g$
$∵ 1$ mole of $C u S O_{4}$ contains $1$ mole of copper, i.e.,
$159.5 g$ of $C u S O_{4}$ contains $63.5 g$ of copper
Therefore,
$100 g$ of $C u S O_{4}$ will contain of copper $= \frac{63.5 \times 100}{159.5} = 39.81 g$

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