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Question

How much current is required to deposit 0.195g of elemental Pt from a solution containing [PtCl6]2  ion with a time period of 2 hrs?  (Atomic Mass of Pt = 195)
  1. 0.054A
  2. 0.214A
  3. 0.428A
  4. 0.027A


Solution

The correct option is A 0.054A
[PtCl6]2 or Pt4++4ePt
4 × 96500C of electricity will deposit Pt = 195g.
195g of Pt will be deposited by 96500 × 4C
  0.195g of Pt will be deposited b y
96500×4×0.195195
Currrent (I) =4×96500×0.195195×2×60×60=0.054A

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