How much electric charge is required to produce $20.0 g$ of calcium from molten $C a C l_{2}$ ?

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Solution

$\to$ 20g of Calcium corresponds to $\frac{20}{40} = 0.5 m o l e s$ of Calcium.
Half Cell reaction for reduction:-
$C a_{(a q)}^{2 +} + 2 e^{-} \to C a_{(s)}$ .
1 mole of $C a$ is produced by passage of 2 mole electrons .
$∴$ 0.5 mole of $C a$ is produced by passage of $0.5 \times 2 = 1 m o l e e^{-}$
Charge on 1 mole electron is Faraday.
$| t h e r e f o r e$ To produce $20 g$ of $C a$ from molten $C a C l_{2}$ , 1 Faraday of electric charge is required.

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