Question

How much electricity in terms of Faraday is required to produce $100$g of Ca from molten $CaC{l}_2$?

• A. $1$ F
• B. $2$ F
• C. $3$ F
• D. $5$ F

Answer 1

The correct option is D $5$ F

We have to note that one mole of electron charge is equivalent to one Faraday.

Given reaction,

$CaC{l}_2\to C{a}^{2+}+2C{l}^{-}$

Ca is undergoing oxidation i.e, $C{a}^{2+}+2e^{-}\to Ca$

We can observe that 40g of Ca takes $2e^{-}$ charge,

So,1 mole of $Ca\left(40g\right)\equiv 2F$

Now, 100g of $Ca\equiv 5F$