How much energy is transferred when 10 A current flows through a resistor of 5 ohm for 30 minutes?
1.2 kWh
0.25 kWh
0.025 kWh
3.2 kWh
P = I2 R = (10)2 × 5 = 500 watt = 0.5 kW
t = 30 minute = 0.5 hr
E = P × t = 0.5 kW × 0.5 hr = 0.25 kWh