How much heat energy is released when 5.0 g of water at 200C changes to ice at 00C? Take specific heat capacity of water equal to 4.2 Jg−1C−1, specific latent heat of fusion of ice = 336 Jg−1.
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Solution
Mass of water m = 5.0 g
specific heat capacity of water c = 4.2Jg−1K−1 specific latent heat of fusion of iceL = 336Jg−1
Amount of heat energy released when 5.0 g of water at 20oC changes into water at 0oC = 5 x 4.2 × 20 = 420 J.
Amount of heat energy released when 5.0g of water at 0oC changes into ice at 0oC = 5 × 336J = 1680 J.
Total amount of heat released = 1680 J + 420 J = 2100 J.