wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

How much heat energy is released when 5.0 g water at 42C changes into ice at 0C? Take specific heat capacity of water = 4.2Jg1, specific latent heat of fusion of ice = 336Jg1 :

A
21J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4200J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
42J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2562J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 2562J
Heat released Q=mL+mc(420)
Q=5×336+5×4.2×42
Q=2562J

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Calorimetry
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon