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1st Law of Thermodynamics

How much heat...

Question

How much heat energy is required to prepare a water bath of $20 k g$ , when cold water at $10^{o} C$ is heated to $40^{o} C$ ? (Specific heat capacity of water is $4200 J / k g^{o} C$ ) :

252000000 J

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252000 J

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25200 J

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2520000 J

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Solution

The correct option is C $2520000 J$
Temperature raise is $40 - 10 = 30^{o} C$
heat required $= m s Δ T$
$= 20 \times 4200 \times 30 = 2520000 J$

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